DateTime subtractDays: Difference between revisions

Latest revision as of 09:49, 21 December 2011

Return datetime after subtracting days

Syntax

DateTime_subtractDays(datetime,n)

Arguments

Return value

array, in which there are 9 items:

Index	Data type	Value
DateTime_Year	number	Value after the calculation
DateTime_Month	number	Value after the calculation
DateTime_Day	number	Value after the calculation
DateTime_Hour	number	Value after the calculation
DateTime_Minute	number	Value after the calculation
DateTime_Second	number	Value after the calculation
DateTime_Millisecond	number	Value after the calculation
DateTime_Week	number	Value after the calculation
DateTime_TimeZone	number	Value of input date time object array

Example

number n = 4;

array a1 = {2009,6,19,0,0,0,0,25,40};

array a2 = DateTime_subtractDays(a1,n);

print(a2);

// a2 = {2009,6,15,0,0,0,0,25,40}

Availability

Version 5.7

@@ Line 1: / Line 1: @@
-[[Category:General_Functions]]
+{{HelpFiles}}
-{{HelpFiles}}
 ==== DateTime_subtractDays  ====
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 array, in which there are 9 items:
-{| width="876" cellpadding="2" border="1" class="tableintopic" style="border-collapse: collapse; border: 1px solid rgb(1, 1, 1);"
+{| width="876" cellpadding="2" border="1" style="border-collapse: collapse; border: 1px solid rgb(1, 1, 1);" class="tableintopic"
 |- valign="top" align="left"
 | width="198" bgcolor="#c0c0c0" style="border: 1px solid rgb(1, 1, 1);" |
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 ''number n = 4; ''
-''array a1 = {2009,6,19,0,0,0,0,33,40}; ''
+''array a1 = {2009,6,19,0,0,0,0,25,40}; ''
 ''array a2 = DateTime_subtractDays(a1,n); ''
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 ''print(a2);''
-''// a2 = {2009,6,15,0,0,0,0,33,40} ''
+''// a2 = {2009,6,15,0,0,0,0,25,40} ''
 '''Availability'''
 Version 5.7 __NOTOC__ <!-- imported from file: 7547.htm-->
+[[Category:General_Functions]]