Folder_getFolderByResourceId
Syntax
Folder_getFolderByResourceId(Folder_resource_id)
Arguments
Folder_resource_id: Is an expression of the type number.
Return type
Array
Examples
array a=Folder_getFolderByResourceId(2128);
print(a);
// output {28,2128,Administration,1,2071,True,0,False,Administration}
Availability
Version 5.8